The companion explainer, A geometric view of Laplace transform behavior, places the transforms of sin⁡bx\sin bx and cos⁡bx\cos bx on a circle: a radius r=t2+b2r=\sqrt{t^2+b^2} and an angle θ\theta. Replace the oscillating input by a growing one, sinh⁡bx\sinh bx or cosh⁡bx\cosh bx, and the circle no longer fits. Chapter 3 of Rida Abu-Sokon's book replaces it by the hyperbola t2−b2=constt^2-b^2=\text{const}. This article explains why that is the natural move, where it is valid, and how the two pictures compare.

Two ways to measure a point

A point (t,b)(t,b) can be measured with the Euclidean form t2+b2t^2+b^2 or with the indefinite form t2−b2t^2-b^2. The first is preserved by rotations and is parameterized by cos⁡2θ+sin⁡2θ=1\cos^2\theta+\sin^2\theta=1. The second is preserved by hyperbolic rotations (Lorentz boosts, in the language of special relativity) and is parameterized by cosh⁡2φ−sinh⁡2φ=1\cosh^2\varphi-\sinh^2\varphi=1. Which one is appropriate for a Laplace transform depends on the input: an oscillation eibxe^{ibx} produces the factor t−ibt-ib, whose modulus is Euclidean, while a growth ebxe^{bx} produces the real factor t−bt-b, whose natural companion is t+bt+b, and (t−b)(t+b)=t2−b2(t-b)(t+b)=t^2-b^2.

The hyperbolic parameters

For t>∣b∣t>|b| define the Minkowski-type radius and the hyperbolic angle

rˉ=t2−b2,φ=artanh⁡bt,so thatt=rˉcosh⁡φ,b=rˉsinh⁡φ.\bar r=\sqrt{t^2-b^2},\qquad \varphi=\operatorname{artanh}\frac{b}{t},\qquad\text{so that}\quad t=\bar r\cosh\varphi,\quad b=\bar r\sinh\varphi .

The key identities are the hyperbolic analogues of t±ib=re±iθt\pm ib=re^{\pm i\theta}:

t−b=rˉ e−φ,t+b=rˉ eφ,e2φ=t+bt−b.t-b=\bar r\,e^{-\varphi},\qquad t+b=\bar r\,e^{\varphi},\qquad e^{2\varphi}=\frac{t+b}{t-b}.

These identities suggest the most transparent coordinates for the hyperbolic regime: the pair u=t+bu=t+b and v=t−bv=t-b, often called light-cone coordinates. In them the invariant is a product, rˉ 2=uv\bar r^{\,2}=uv, and the hyperbolic angle is a ratio, e2φ=u/ve^{2\varphi}=u/v. A hyperbolic rotation by α\alpha multiplies uu by eαe^{\alpha} and divides vv by eαe^{\alpha}, leaving uvuv unchanged. Compare the circular case, where a rotation multiplies t+ibt+ib by eiαe^{i\alpha} and leaves ∣t+ib∣|t+ib| unchanged. Every Laplace transform of an exponential input is a power of uu or of vv, which is why the hyperbolic formulas below are so compact.

The word "angle" deserves a comment. A circular angle θ\theta is twice the area of the sector of the unit circle it cuts off. A hyperbolic angle has the same description with the unit hyperbola t2−b2=1t^2-b^2=1: the region bounded by the two rays from the origin to (1,0)(1,0) and (cosh⁡φ,sinh⁡φ)(\cosh\varphi,\sinh\varphi) and by the hyperbola has area φ/2\varphi/2. So φ\varphi is a genuine measure attached to the hyperbola, even though it is unbounded and is not an angle in the Euclidean sense.

Exponentials, sinh and cosh

With these parameters the elementary growing inputs take a uniform shape:

L{ebx}(t)=1t−b=eφrˉ,L{e−bx}(t)=1t+b=e−φrˉ,\mathcal{L}\{e^{bx}\}(t)=\frac{1}{t-b}=\frac{e^{\varphi}}{\bar r},\qquad \mathcal{L}\{e^{-bx}\}(t)=\frac{1}{t+b}=\frac{e^{-\varphi}}{\bar r},
L{cosh⁡bx}(t)=tt2−b2=cosh⁡φrˉ,L{sinh⁡bx}(t)=bt2−b2=sinh⁡φrˉ.\mathcal{L}\{\cosh bx\}(t)=\frac{t}{t^2-b^2}=\frac{\cosh\varphi}{\bar r},\qquad \mathcal{L}\{\sinh bx\}(t)=\frac{b}{t^2-b^2}=\frac{\sinh\varphi}{\bar r}.

Compare cos⁡θ/r\cos\theta/r and sin⁡θ/r\sin\theta/r in the oscillatory case. The structure is identical; only the functions and the radius have changed.

Lifting in the hyperbolic regime

Multiplying the input by xnx^n differentiates the transform nn times in tt, so L{xne±bx}=n!/(t∓b)n+1=n! e±(n+1)φ/rˉ n+1\mathcal{L}\{x^ne^{\pm bx}\}=n!/(t\mp b)^{n+1}=n!\,e^{\pm(n+1)\varphi}/\bar r^{\,n+1}. Adding and subtracting gives the hyperbolic counterparts of angular lifting:

L{xnsinh⁡bx}(t)=n! sinh⁡((n+1)φ)rˉ n+1,L{xncosh⁡bx}(t)=n! cosh⁡((n+1)φ)rˉ n+1,t>∣b∣.\mathcal{L}\{x^n\sinh bx\}(t)=\frac{n!\,\sinh\big((n+1)\varphi\big)}{\bar r^{\,n+1}},\qquad \mathcal{L}\{x^n\cosh bx\}(t)=\frac{n!\,\cosh\big((n+1)\varphi\big)}{\bar r^{\,n+1}},\qquad t>|b|.
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One qualitative difference stands out immediately. In the circular case, sin⁡((n+1)θ)\sin((n+1)\theta) changes sign as the angle sweeps, so L{xnsin⁡bx}\mathcal{L}\{x^n\sin bx\} has zero rays in the parameter plane. In the hyperbolic case, sinh⁡((n+1)φ)\sinh((n+1)\varphi) has the sign of bb and never vanishes for b≠0b\neq 0, and cosh⁡\cosh is always positive. Growing inputs produce transforms without sign changes; there is nothing to "quantize".

A Pythagorean pair of points

Evaluate L{xsinh⁡3x}\mathcal{L}\{x\sinh 3x\} and L{x2sinh⁡3x}\mathcal{L}\{x^2\sinh 3x\} at t=5t=5, and compare with L{xsin⁡3x}\mathcal{L}\{x\sin 3x\} at t=4t=4.

  1. At (t,b)=(5,3)(t,b)=(5,3): rˉ=25−9=4\bar r=\sqrt{25-9}=4 and e2φ=(5+3)/(5−3)=4e^{2\varphi}=(5+3)/(5-3)=4, so φ=ln⁡2\varphi=\ln 2 exactly.
  2. For n=1n=1: sinh⁡(2ln⁡2)/42\sinh(2\ln 2)/4^2. Since sinh⁡(2ln⁡2)=(4−14)/2=158\sinh(2\ln 2)=(4-\tfrac14)/2=\tfrac{15}{8}, the value is 15/12815/128. The textbook form 2bt/(t2−b2)2=30/2562bt/(t^2-b^2)^2=30/256 agrees.
  3. For n=2n=2: 2sinh⁡(3ln⁡2)/432\sinh(3\ln 2)/4^3, and sinh⁡(3ln⁡2)=(8−18)/2=6316\sinh(3\ln 2)=(8-\tfrac18)/2=\tfrac{63}{16}, giving 63/51263/512.
  4. The circular companion (t,b)=(4,3)(t,b)=(4,3) has r=5r=5 and sin⁡2θ=2⋅35⋅45=2425\sin 2\theta=2\cdot\tfrac35\cdot\tfrac45=\tfrac{24}{25}, so L{xsin⁡3x}(4)=24/625\mathcal{L}\{x\sin 3x\}(4)=24/625.
  5. Each value was confirmed by numerical integration of the defining Laplace integral.
L{xsinh⁡3x}(5)=15128,L{x2sinh⁡3x}(5)=63512,L{xsin⁡3x}(4)=24625\mathcal{L}\{x\sinh 3x\}(5)=\tfrac{15}{128},\quad \mathcal{L}\{x^2\sinh 3x\}(5)=\tfrac{63}{512},\quad \mathcal{L}\{x\sin 3x\}(4)=\tfrac{24}{625}

The formal bridge between the two

The two pictures are linked by the substitution b↦ibb\mapsto ib. Under it, r=t2+b2r=\sqrt{t^2+b^2} becomes t2−b2=rˉ\sqrt{t^2-b^2}=\bar r, and the principal-branch identity arctan⁡(ix)=iartanh⁡(x)\arctan(ix)=i\operatorname{artanh}(x) for ∣x∣<1|x|<1 turns iθi\theta into −φ-\varphi. The oscillatory formula L{xneibx}=n! ei(n+1)θ/rn+1\mathcal{L}\{x^ne^{ibx}\}=n!\,e^{i(n+1)\theta}/r^{n+1} then becomes n! e−(n+1)φ/rˉ n+1=L{xne−bx}n!\,e^{-(n+1)\varphi}/\bar r^{\,n+1}=\mathcal{L}\{x^ne^{-bx}\}. The book describes this as an analytic continuation that changes the metric from Euclidean to Minkowski-type, rather than a rotation within the complex plane.

Side by side

Circular (bounded input)Hyperbolic (growing input)
Typical inputsin⁡bx, cos⁡bx, eibx\sin bx,\ \cos bx,\ e^{ibx}sinh⁡bx, cosh⁡bx, e±bx\sinh bx,\ \cosh bx,\ e^{\pm bx}
Invariant formt2+b2=r2t^2+b^2=r^2t2−b2=rˉ 2t^2-b^2=\bar r^{\,2}
Angleθ=arctan⁡(b/t)\theta=\arctan(b/t)φ=artanh⁡(b/t)\varphi=\operatorname{artanh}(b/t)
Coordinatest=rcos⁡θ, b=rsin⁡θt=r\cos\theta,\ b=r\sin\thetat=rˉcosh⁡φ, b=rˉsinh⁡φt=\bar r\cosh\varphi,\ b=\bar r\sinh\varphi
Valid regiont>0t>0, any real bbt>∣b∣t>|b|
Lifted familyn!sin⁡((n+1)θ)/rn+1n!\sin((n+1)\theta)/r^{n+1}n!sinh⁡((n+1)φ)/rˉ n+1n!\sinh((n+1)\varphi)/\bar r^{\,n+1}
Sign changesyes, on rays θ=kπ/(n+1)\theta=k\pi/(n+1)none
Boundary behaviorno singularity for t>0t>0pole on t=∣b∣t=|b|
Circular versus hyperbolic representation of Laplace transforms of elementary inputs.

The table is a reminder that "geometry" here is a choice of coordinates adapted to the input, not a change in the transform. Both columns describe the same classical integral; they differ in which quadratic form makes the answer simplest.

The same split elsewhere

The circular/hyperbolic dichotomy is not special to Laplace transforms. It appears wherever a quadratic expression changes sign.

  • Differential equations. y′′+b2y=0y''+b^2y=0 has characteristic roots ±ib\pm ib and solutions cos⁡bx,sin⁡bx\cos bx,\sin bx; y′′−b2y=0y''-b^2y=0 has roots ±b\pm b and solutions cosh⁡bx,sinh⁡bx\cosh bx,\sinh bx. Their Laplace transforms carry the denominators t2+b2t^2+b^2 and t2−b2t^2-b^2 respectively.
  • Rational functions. The derivatives of 1/((x−p)2+q2)1/\big((x-p)^2+q^2\big) are sines of multiple angles, while those of 1/((x−p)2−q2)1/\big((x-p)^2-q^2\big) are hyperbolic sines of multiple hyperbolic parameters; see Understanding root geometry in rational functions.
  • Conic sections. t2+b2=1t^2+b^2=1 is a circle and t2−b2=1t^2-b^2=1 is a hyperbola; the parameterizations by (cos⁡,sin⁡)(\cos,\sin) and (cosh⁡,sinh⁡)(\cosh,\sinh) are the two standard choices.

In each case the sign of a discriminant-like quantity decides whether the natural coordinates are circular or hyperbolic, and the passage between them is the formal substitution of ibib for bb. Recognizing the pattern once saves relearning it in every course.

Classical results and the book's framework

References

  1. Rida Jamal Badawi Abu-Sokon. Analytical Methods for Higher-Order Derivatives, Integral Transforms, and Matrix-Based Techniques, First edition. Kindle Direct Publishing, 2026. Chapter 3, §3.0.1–3.0.4 and §3.0.10.
  2. F. W. J. Olver et al. (eds.). NIST Digital Library of Mathematical Functions, Chapter 4 Elementary Functions. National Institute of Standards and Technology. Hyperbolic functions and their inverses, including principal branches..
  3. F. W. J. Olver et al. (eds.). NIST Digital Library of Mathematical Functions, §1.14 Integral Transforms. National Institute of Standards and Technology. Laplace transform and its region of convergence..
  4. Lokenath Debnath and Dambaru Bhatta. Integral Transforms and Their Applications, Third edition. CRC Press, 2014. Laplace transforms of exponential and hyperbolic functions. Cited in the book's bibliography..